Intermediate Mass Stars

Intermediate Mass Stars

4-5 Intermediate Mass Stars and Supernovae

Introduction: We’ve now followed the life of a low-mass star from its birth as a main sequence star to its death as a black dwarf or a Type Ia supernova. Low-mass stars only have the chance to go out with a bang if they are fortunate enough to collect a large amount of mass from a companion star. The Sun is doomed to end its life as a black dwarf. However, intermediate-mass stars are destined to have a much more exciting end and you’ll learn about that in this lesson.

Reading: Ch. 22, section 22.5 and ch. 23, section 23.2 and 23.3

Lesson: Much of the evolution we’ve learned for low-mass stars does apply to intermediate- and high-mass stars. All main sequence stars fuse hydrogen into helium. However, high-mass stars take a slightly different approach to those nuclear processes. A low-mass star will form helium by starting with two hydrogen nuclei and banging them together to form deuterium. We already know that you can take deuterium and fuse it to form helium. Since this process starts with two hydrogen nuclei, which are just protons, this process is often called the proton-proton chain or simply, the pp chain. More massive stars use carbon as a catalyst to the reaction, combining hydrogen with carbon to form nitrogen. Through a series of steps, the helium nucleus is formed and the carbon nucleus is reclaimed so it can be used for another reaction.

Otherwise, the evolution of an intermediate-mass star is very similar to that of a low-mass star. It will exhaust hydrogen fusion in its core, begin shell hydrogen fusion, ignite helium fusion in the core, and ignite helium shell fusion. However, intermediate- and high-mass stars have a strong enough gravity that they can compress the core up to temperatures required to begin carbon fusion. Rather than electron degeneracy setting in, the core continues fusion reactions and continues to live for a while as carbon is fused to form neon. Various phases of fusion occur in the core of the star, as is shown in the following figure:

As you can see, the star goes through many fusion stages before the end. Whenever one fuel source runs out, the core begins to contract while a new form of shell fusion begins. Each successive fusion process lasts for a shorter period of time than the last. Just as the triple-alpha process lasts for a shorter time than the main sequence lifetime, so carbon fusion lasts for a shorter time than the triple-alpha process. For a 25-solar mass star, carbon fusion lasts for only around 600 years, not the millions of years we would expect. Silicon fusion, which creates the iron core, will last for only one day in the core of a 25-solar mass star. We can just guess that this is leading up to a quick and explosive finale. Once the core is composed of iron, it is time for the death of the intermediate-mass star.

Why does fusion stop at iron?

There are two ways that you can produce energy through nuclear processes. One way is to take heavy nuclei and break them apart into lighter nuclei, releasing energy in the process. This is called nuclear fission. Typical elements which are used for this process are uranium and plutonium.

We’ve talked rather extensively about the opposite process, nuclear fusion, in which light elements are fused together to form heavier elements and energy is released. As you probably already know, there really is no free lunch in nature. The fact that there is fission and fusion seems to indicate that we can take heavy elements and break them down into light elements to gain energy. We can then take those light elements and fuse them to gain energy. This is essentially saying that we could generate an infinite amount of energy from a single uranium nucleus. Clearly, this cannot be the case in reality. As it turns out, there is a break-even point, a point where you can no longer use fission to release energy and a point where you can no longer use fusion to release energy. This point lies at the element iron. You cannot fuse iron into heavier elements and get more energy out of the reaction than what you put into it. You also cannot break apart an iron nucleus and get more energy out of the reaction than what you put into it. Once the core becomes composed of iron, the star is stuck and the core will no longer undergo fusion processes.

We’ve seen this before for low-mass stars. The core can no longer undergo fusion reactions. The core will contract until the point where electron degeneracy begins to become important. However, where the contraction will be halted for a low-mass stellar core, intermediate- and high-mass stars have stellar cores more massive than the 1.4-solar mass Chandrasekhar mass limit, the maximum mass which can be supported by electron degeneracy pressure. So, what happens now? The electrons still vehemently refuse to be in the same energy state but they have nowhere to go. Well, actually, they do have somewhere to go. The electrons in the core of the star can be crushed into the protons. If you look at the masses of electrons, protons, and neutrons, you’ll find that the mass of a neutron is similar to the combined masses of a proton and an electron. When you force an electron and proton together, they form neutrons.

At this point, a lot happens nearly at once. The combining of the protons and electrons makes the core collapse rapidly, taking less than one second to finish this process. The core rapidly becomes composed of neutrons. As it turns out, neutrons follow a similar exclusion principle, so there is now the buildup of neutron degeneracy pressure. For an intermediate-mass star, the neutron degeneracy pressure is strong enough to bring a rapid halt to the core collapse. The resulting shock wave from the core bounce combines with the rapid release of energy from the fusion of the electrons and protons. Neutrinos are produced in this proton-electron reaction. As we know, neutrinos are nearly unreactive, but with so many of them being produced at once, they interact sufficiently with the outer layers of the star that the neutrinos accelerate them outward. The net result is a huge stellar explosion called a Type II supernova. These outer layers of the star are ejected at speeds in excess of 10,000 km/s and with an energy roughly equal to the total amount of energy that the Sun will produce during its entire main sequence lifetime. You can see a nice animation of a supernova explosion by clicking here (or here if you have a broadband connection).

Where do the other elements come from?

So far, we’ve learned that a low-mass star will produce carbon (and possibly neon and oxygen) in its core. Intermediate- and high-mass stars produce elements up to iron in their cores. That’s great and all, but what about the rest of the periodic table? Where do elements like gold, silver, and uranium come from?

As you may have guessed, they come from a supernova. You can’t fuse iron into heavier elements and get energy out of the process. However, if you have a lot of energy to spare, as you do in a supernova explosion, you can put energy into the process and get iron to fuse with loose neutrons and protons to form heavier elements. Thus, supernovae not only produce all of the heaviest elements, they are also the mechanism by which these materials are shot out into space, where they can eventually be incorporated into new stars, planets, and other bodies. It has been said that we are made of star stuff and this is the very reason why.

A supernova explosion can be bright enough that it can outshine the entire galaxy in which the star is located.

This is a picture of Supernova 1987A, a supernova which occurred in the Large Magellanic Cloud, a mere 150,000 light-years from us. On average, astronomers believe that supernovae occur in a galaxy once per century and the last one to occur in the Milky Way was roughly 300 years ago, so we are long overdue. When the next one does go off in our galaxy, astronomers are sure to be in for a scientific treat.

 

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